x^2=16+(x-4)*(x+4)

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Solution for x^2=16+(x-4)*(x+4) equation: 


Simplifying
x2 = 16 + (x + -4)(x + 4)

Reorder the terms:
x2 = 16 + (-4 + x)(x + 4)

Reorder the terms:
x2 = 16 + (-4 + x)(4 + x)

Multiply (-4 + x) * (4 + x)
x2 = 16 + (-4(4 + x) + x(4 + x))
x2 = 16 + ((4 * -4 + x * -4) + x(4 + x))
x2 = 16 + ((-16 + -4x) + x(4 + x))
x2 = 16 + (-16 + -4x + (4 * x + x * x))
x2 = 16 + (-16 + -4x + (4x + x2))

Combine like terms: -4x + 4x = 0
x2 = 16 + (-16 + 0 + x2)
x2 = 16 + (-16 + x2)

Combine like terms: 16 + -16 = 0
x2 = 0 + x2
x2 = x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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